Given two inputs a
and b
, let da[t] = abs(a[t] - a[t - 1])
and db[t] = abs(b[t] - b[t - 1])
. Output a[t]
if da[t]
is smaller, and output b[t]
if db[t]
is smaller. If da[t] == db[t]
, use whichever input was used last (assume a
for the first sample of output).
a |
Input signal A. |
b |
Input signal B. |
(
d = { arg amp=1.0;
var in1, in2;
in1 = LFNoise0.ar(800, amp);
in2 = SinOsc.ar(800);
LeastChange.ar(in1, in2) * 0.1;
}.play;
)
d.set(\amp, 0.1);
d.set(\amp, 0);
d.set(\amp, 3);
d.free;
the control that changed least is used as output:
xxxxxxxxxx
(
d = { arg freq=440;
var internalFreq;
internalFreq = LFNoise0.ar(0.3, 300, 800);
SinOsc.ar(
LeastChange.kr(freq, internalFreq) // two sources of change: one external, one internal
) * 0.1
}.play
);
d.set(\freq, 800);
d.set(\freq, 900);
d.free;